Mathematics-Online lexicon: Basis of Eigenvectors

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	Mathematics-Online lexicon:
	Basis of Eigenvectors

A B C D E F G H I J K L M N O P Q R S T U V W X Y Z

If there exists a basis of eigenvectors

associated with eigenvalues $\lambda_j$ of a given matrix

, then

$\displaystyle B^{-1} A B = \operatorname{diag}(\lambda_1,\ldots,\lambda_n), \quad B = (b_1,\ldots,b_n) \,.$

(Authors: App/Burkhardt/Höllig)

Example:

automatically generated 3/16/2005