Mathematics-Online course: Preparatory Course Mathematics-Linear Algebra and Geometry-Systems of Linear Equations-Gauss Elimination to Echelon Form

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	Mathematics-Online course: Preparatory Course Mathematics - Linear Algebra and Geometry - Systems of Linear Equations
	Gauss Elimination to Echelon Form

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By Gaussian elimination any LSE can be brought to row-echelon form:

$\displaystyle Ax = b \rightarrow \underbrace{ \left(\begin{array}{cccc ccc} ... ...ht) = \left(\begin{array}{c} c_1 \\ \vdots \\ c_m \end{array}\right)\, ,$

where the so called pivots

$\displaystyle p_1=a'_{1,j_1},\ldots,p_k=a'_{k,j_k},\quad 1\le j_1<\cdots<j_k\le n\, ,$

are not equal to zero and

is the rank of

In detail the $\ell$ -th elimination step proceeds as follows:

Select as pivot $p_\ell$ an element $\ne 0$ with smallest possible column-index $j_\ell$ and row-index $\ge \ell$ . Interchange the $\ell$ -th equation with the equation which contains the pivot.
If there is no possible pivot, the echelon form is reached.
For $i>\ell$ an appropriate multiple of the $\ell$ -th equation is subtracted from the -th equation so that $a_{i,j_\ell}$ equals zero.

(Authors: Burkhardt/Höllig/Streit)

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automatically generated 1/9/2017