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Mathematics-Online problems:

Interactive Problem 372: LSE without Parameters

A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
Solve the following linear system of equations:

\begin{displaymath} \begin{array}{rcrcrcrcc} x_1 & + & 2x_2 & - & 2x_3 & + & ... ...= & 0\\ -x_1 & + & x_2 & + & 4x_3 & & & = & 0 \end{array} \end{displaymath}

Solution: not specified

The LSE has

$ \rule[-0.5ex]{0pt}{2ex}$ no solution .
$ \rule[-0.5ex]{0pt}{2ex}$ exactly one solution ,
$ \rule[-0.5ex]{0pt}{2ex}$ infinitely many solutions ,
$ \rule[-0.5ex]{0pt}{2ex}$ $ \rule[-0.5ex]{0pt}{2ex}$ $ \rule[-0.5ex]{0pt}{2ex}$ $ \rule[-0.5ex]{0pt}{2ex}$
$ \rule[-0.5ex]{0pt}{2ex}$ namely $ x_1=$ , $ \rule[-0.5ex]{0pt}{2ex}$ $ x_2=$ , $ \rule[-0.5ex]{0pt}{2ex}$ $ x_3=$ , $ \rule[-0.5ex]{0pt}{2ex}$ $ x_4=$ .
$ \rule[-0.5ex]{0pt}{2ex}$ namely $ x_1=r$ , $ \rule[-0.5ex]{0pt}{2ex}$ $ x_2=$ $ r$ , $ \rule[-0.5ex]{0pt}{2ex}$ $ x_3=$ $ r$ , $ \rule[-0.5ex]{0pt}{2ex}$ $ x_4=$ $ r$ .

Specify the solution rounded on three decimal places if it is necessary.


   

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  automatically generated: 8/11/2017