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Mathematics-Online problems:

Interactive Problem 32: Jordan Form

A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
Find the Jordan canonical form $ J$ of the matrix

\begin{displaymath} A=\left( \begin{array}{rrr} -1& 2& -1\\ -8&-10& 8\\ -15&-14& 13\\ \end{array}\right)\,. \end{displaymath}

Give the entries on the diagonal in ascending order.
$ J= \left(\rule{0pt}{6ex}\right.$
0
0
0 0
$ \left.\rule{0pt}{6ex}\right)$

   
(Authors: App/Höfert)

Solution:

[Links]
  automatically generated: 8/11/2017